Coefficient of static friction? - friction static of a ladder
At 6 feet long, with a uniform standard is against a wall without friction, an angle of 69.3 degrees on the ground. The scale has a mass M = 31.7 kilograms. A mm = 82.42 kilograms man to 82 percent of the way to the top of the ladder when he slips and falls.
A. What is the coefficient of static friction between the conductor and the ground?
Monday, February 1, 2010
Friction Static Of A Ladder Coefficient Of Static Friction?
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Mass. man = mm
Mass scale = MI
In response to the wall friction, the wall perpendicular to the wall is
A normal response of the plant = R = [ml + mm] g
R = [ml + mm] g N = 1118,376
As the man rises to 82 percent of the way to the top of the stairs
Man near the top of the stairs = 0.18L
Frictional force f =
Wide angle with the ground = O = 69.3 degrees
Among moment when the top level of prejudice to the wall,
Due to the weight of the man = t1 = * g * mm 0.18LcosO moment counterclockwise
Moment by the weight of the scale = t2 = ml * g * 0.5LcosO counterclockwise
Torque due to friction = t3 = ....... Face fLsinO
Reaction time due to normal = T4 = [ml + mm] gLcos O clockwise
When the supervisor is to couple membrane is zero, which means
Sum of pairs in the opposite direction clockwise torque = sum
0.18LcosO mm * g * g * + ML * 0.5LcosO + fLsinO = [ml + mm] gLcos O
\\ \\ \\ \\ \\ \\ \\ \\ U0026lt;simplify br> The division of both sides with LCOS and,
Tano = f [mm + ml] g-(mm * + g * 0.18 ml * g * 0.5)
Tano f = [0.82 mm 0.5 ml] g
f = [0.82 mm 0.5 ml] g / Tano
f = [0.82 * 82.42 0.5 * 31.7] * 9.8 / tan69.3
f = [67.404 + 16.85] * 9.8 / 2.6464 = 312.0019 N
Coefficient of static friction = F / R = 312.0019 / 0,279 = 1118,376
the coefficient of static friction between ladder and ground is 0279
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